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3.5x^2+5x-3=0
a = 3.5; b = 5; c = -3;
Δ = b2-4ac
Δ = 52-4·3.5·(-3)
Δ = 67
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{67}}{2*3.5}=\frac{-5-\sqrt{67}}{7} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{67}}{2*3.5}=\frac{-5+\sqrt{67}}{7} $
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